Arepair person is scheduled to be at your apartment between 9: 00am to 12: 00pm but you have to leave at 11: 30 to out a friend. if the repair person is equally likely to be at your apartment any time during the appointment time, what is the probability that you will be there?
a 16.7%
b 50%
c 83.3%
d 91.2%

Option C is the correct answer.

Step-by-step explanation:

Probability is the ratio of number of favorable outcome to total number of outcomes.

Here we need to find probability that  repair person is equally likely to be at your apartment any time during the appointment time.

A repair person is scheduled to be at your apartment between 9:00am to 12:00pm.

Total duration for which repair person available = 3 hours.

You have to leave at 11:30 to help out a friend,

Time you are available at home during this 9:00am to 12:00pm, is 9:00am to 11:30 am

Duration favorable = 11:30 - 9:00 = 2:30 hours = 2.5 hours

Option C is the correct answer.

tip $2.90

total $17.40

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)