Arectangular piece of land whose length is twice its width has a diagonal distance of 90 yards. how many yards, to the nearest tenth of a yard, does a person save by walking diagonally across the land instead of walking its length and its width?

A person saves 30.7 yards

Step-by-step explanation:

the path a person walks diagonally creates a right triangle with the lenght and the width of the rectangular piece of land. The diagonal is 90 yards which becomes the hypotenuse.

let w be the width, then l becomes the length, which is twice the width. Therefore, leg l=2a and leg w=a.

By the Pythagorean Theorem:

Replacing the values:

But that a is the value for the width, if a person walks the width and the length, it becomes:

the length plus the width=2a+a=3a.

So:

Now, the difference between walking across the land and surrounding it, is:

We can conclude, a person saves 30.7 yards if walking across the land.

the answer is 2/54

step-by-step explanation:

1.3 million hoops i believe