Louisiana is busy designing new lottery scratch-off games. in the latest game, bayou boondoggle, the player is instructed to scratch off one spot: a, b or c. a can reveal "loser," "win $1," or "win $50." b can reveal loser or "take a second chance." c can reveal "loser" or "win $500." on the second chance players are asked to scratch off d or e. d can reveal "loser" or "win $1." e can reveal "loser" or "win $10." the probabilities at a are .9, .09 and .01. the probabilities at b are 0.8 and 0.2. the probabilities at c are .999 and .001. the probabilities at d are 0.5 and 0.5. finally, the probabilities at e are 0.95 and 0.05. draw the decision tree that represents this scenario. use proper symbols and label all branches clearly. calculate the expected value of this game.

use this formula:

p(a\b) = p(a and b)/p(b).

take it from here.

i can't solve unless i know what the line is

step-by-step explanation:

welcome to/p>

let's cover over the formula of the vertex:

y = a(x – h)^2 + k

in this formula, (h,k) are the vertex, always remember that the positive or negative value of the vertex is based on the sign it has.

for example, if the vertex is -3,-6 then both the x and y value would have the positive sign attached to it and if it were a positive x and y value, then a negative sign would be attached to it.

with that being said, for our problem the x value is a positive one so we are looking for a number with a negative sign next to it, in this case the first and second choice.

however, for the first answer choice it isn't quite part of the formula so we know that the answer choice correctly displays the x value.

to confirm, we can see if the -1 fits correctly with the second answer choice, and as mentioned above a negative number will have a positive sign attached to it. so, for our problem we can see that -1 has been changed to +1, so we can confirm that the second answer choice is correct.

hence, our final answer is y=(x - 1)^2 + 1