Does the histogram appear to depict data that have a normal distribution?
a. the histogram does not appear to depict a normal distribution. the frequencies generally decrease to a maximum and then increase, and the histogram is symmetric.
b. the histogram appears to roughly approximate a normal distribution. the frequencies generally increase to a maximum and then decrease, and the histogram is symmetric.
c. the histogram appears to roughly approximate a normal distribution. the frequencies generally decrease to a minimum and then increase.
d. the histogram does not appear to depict a normal distribution. the frequencies generally increase and the histogram is symmetric.

B. The histogram appears to roughly approximate a normal distribution. The frequencies generally increase to a maximum and then decrease, and the histogram is symmetric.

Step-by-step explanation:

The Graph of Normal Distribution is like a bell-shaped. Here the value of y is less for the lower value of x and then the value of y is increased for a larger value of x, but after some time value of y is again getting decrease as the value of x increases. For the Histogram to appear to a normal distribution, the graph of histogram must have the same nature. Thus option B is only the correct option.

The histogram is made up of columns bar with no gaps between bars with different labels of numeric data of different heights shows the size of the group of different labels.

Option B) The histogram appears to roughly approximate a normal distribution. The frequencies generally increase to a maximum and then decrease, and the histogram is symmetric.    

Step-by-step explanation:

We are given the following information in the question:

Yes, histograms can be used to depict the the normality of a distribution.

Option B) The histogram appears to roughly approximate a normal distribution. The frequencies generally increase to a maximum and then decrease, and the histogram is symmetric.

yes

step-by-step explanation:

so of course you want to start by plugging the 5 in which goes to 7(5)+3(5)=50 because 7*5=35 and 3*5=15 and then add them together, then plug in the 5 to the other equation as well 9(5)+5=50 because 9*5= 45 and then add 5 and so yes they are equivalent.