53. use the graph off to sketch the graphs.
(a) y = f(x) + 2 (b) y = -f(x)
(c) y = f(x - 2) (d) y = f(x + 3)
(e) y = f(x) - 1 (f) y = f(-x)
(-2, 4) f
+
(42)
(0,3)
127(1,0) f
(3,1)
(1,0)
2
270,-1) 4
t-27 (3,-1)

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step-by-step explanation:

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i cant answer this, theres no table. sorry man

step-by-step explanation:

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true