Graham is hiking at an altitude of 14,040 feet and is descending 50 feet each minute. max is hiking at an altitude of 12,500 feet and is ascending 20 feet each minute . how many minutes will it take graham and max to meet at the same altitude

The answer to your question is: 51.33 min

Step-by-step explanation:

Data

                         Graham                        Max

height              14040 ft                       12500 ft       difference  = 1540 ft

speed               50 ft/min                     20 ft/ min

Formula

                 v = d/t   clear d from this equation d = vt

Equation

                    Graham             Max

                       50t        =     1540 + 20t

Solve it          50t - 20t = 1540

                     30t = 1540

                     t = 1540 / 30

                     t = 51.33 min

i dont get it. where are the "descriptions"?

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below: