In the diagram, rt bisects ∠srq, and m∠qrt = 55°. find m∠srq.

∠SRQ = 110°

Step-by-step explanation:

Since RT bisects ∠SRQ, then

∠SRT= ∠QRT - 55° and

∠SRQ = ∠SRT + ∠QRT = 55° + 55° = 110°

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)