You invest $1,000 in a complete portfolio. the complete portfolio is composed of a risky asset with an expected rate of return of 16% and a standard deviation of 20% and a treasury bill with a rate of return of 6%. the slope of the capital allocation line formed with the risky asset and the risk-free asset is approximately
1.040
0.25
0.50
0.80

The slope of the capital allocation line formed with the risky asset and the risk-free asset is approximately 0.5

Step-by-step explanation:

given data

invested = $1000

rate of return = 16%

standard deviation = 20%

rate of return = 6%

to find out

The slope of the capital allocation line

solution

we know here rate of return equation for find  slope of line that is

R1 = R2 + σ × slope of line    1

here R is rate of return and and σ is standard deviation

put here all value in equation 1

16 = 6 + 20 × slope of line

20 × slope of line = 10

slope of line = 0.5

so

The slope of the capital allocation line formed with the risky asset and the risk-free asset is approximately 0.5

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.