The average weight of a particular box of crackers is 26.0 ounces with a standard deviation of 0.5 ounce. the weights of the
boxes are normally distributed.
a. what percent of the boxes weigh more than 24.5 ounces? (round your answer to the nearest tenth percent.)
b. what percent of the boxes weigh less than 25.0 ounces?
bed
%
percent of boxes
es
b. percent of boxes
bok
int
ences

the answer is b.

step-by-step explanation:

identity property is where 0+whatever number=whatever number. basically 0+ a number.

a28=58

step-by-step explanation:

a1=a1+(n-1)d

a28= 4+ (28-1)2

a28=4+(27)(2)

a28=4+54

a28=58

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!