The post office is at the corner of first street and main street, which forms a right angle. first street intersects with oak street to the north, and main street intersects with oak street to the east. the intersection of main street and oak street forms a y° angle, and tan y° = 5/7. car a drives on main street for 14 miles to arrive at oak street. how far will car b have to travel on first street to get to oak street? round your answer to the nearest tenth of a mile. a. 7.14 milesb. 14 milesc. 20 milesd. 28.14 miles

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

6 cm

step-by-step explanation:

i believe it's a.

i'm not sure on this one, most likely correct.