1) para que valores reais de x o ponto p (3x -6, 2x +4) pertence ao 4º quadrante?

There are no real values of x for point P to belong to the 4 quadrant

Step-by-step explanation:

The question in English is

To what real values of x does the point P (3x -6, 2x +4) belong to the 4th quadrant?

we know that

A point in the fourth Quadrant has the x-coordinate positive and the y-coordinate negative

we have the point

P (3x-6, 2x+4)

----> inequality A  ( x-coordinate must be positive)

---> inequality B ( y-coordinate must be negative)

Solve Inequality A

 -----> (2,∞)

Solve Inequality B

----> (-∞,-2)

The solution of the system is

(-∞,-2) ∩ (2,∞)

therefore

The system has no solution

There are no real values of x for point P to belong to the 4 quadrant

here is your mark brainliest

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.