The owner of a bike shop that produces custom built bike frames has determined that the demand equation for bike frames is given by the equation
d(q) = –6.10q^2 –5q + 1000
where d(q) is the price in dollars and q is the number of bike frames demanded per week. the supply equation for bike frames is
s(q) = 3.20q^2 + 10q – 80
where q is the quantity the supplier will make available per week in the market when the price is p dollars. find the equilibrium point (q, p) rounded to the nearest hundredth.

equilibrium point (10,340)

Step-by-step explanation:

To find the equilibrium point, equal the demand and the supply:

Reorganize the terms in one side and reduce similar terms:

that's a cuadratic equation, solve with the general formula when:

a=9.3, b=15, c=-1080

q can't be negative because it is the quantity of bike frames, so:

This value of q can't be considered.

Then substitute the value of q in D(q) to find the price p:

The equilibrium point (q,p) is (10,340).

i dont know sorry

step-by-step explanation:

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.