The monthly demand for a product is normally distributed with mean = 700 and standard deviation = 200.
1. what is probability demand will exceed 900 units in a month?
2. what is probability demand will be less than 392 units in a month?

 a)  0.1587  b)  0.0618

Step-by-step explanation:

Let x be the random variable that  represents the monthly demand for a product.

Given : The monthly demand for a product is normally distributed with mean = 700 and standard deviation = 200.

i.e.   and  

a) Using formula , the z-value corresponds to x= 900 will be :

Now, by using the standard normal z-table , the probability demand will exceed 900 units in a month :-

Hence, the probability demand will exceed 900 units in a month=0.1587

a) Using formula , the z-value corresponds to x=  392 will be :

Now, by using the standard normal z-table , the probability demand will be less than 392 units in a month :-

Hence, the probability demand will be less than 392 units in a month = 0.0618

126.66 m²

step-by-step explanation:

the pertinent area formula is a = πr², where r is the radius.

here, a = π(6.35 m)² = 40.32π, or approximately 126.66 m²

49%

step-by-step explanation:

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