Mathematics, 14.09.2019 04:30, mistyshaw3736
Let a > 2 and b be positive integers and suppose a|(b! + 1). prove that a > b. hint: follow these steps: aim for a contradiction. suppose the opposite of what you are asked to suppose that a sb. then aſ why? ? we are also given that al(b! + 1). so by problem 4, a will divide the difference of (b! + 1) and b! what does that tell you?
recall that b! = 1.2. (b-2)(b - 1). the product of all natural numbers from 1 to b.
Answers: 1
Mathematics, 21.06.2019 20:30, asdfjk6421
2/3(-6y+9x) expand each expression using the distributive property
Answers: 3
Mathematics, 22.06.2019 02:00, alexi25jeep
Quadrilateral abcd is a parallelogram with diagonals that intersect at point e. which of the following statements is true?
Answers: 1
Let a > 2 and b be positive integers and suppose a|(b! + 1). prove that a > b. hint: follo...
Mathematics, 05.02.2021 21:20
Mathematics, 05.02.2021 21:20