Two resistors have the values as given, r1 = 110ω, and r2 = 560ω. find the equivalent resistance when the two resistors are in series and when the two resistors are in parallel.

SERIES = 670  Ω

PARALLEL = 91.94 Ω

Step-by-step explanation:

Hi, resistors in series obey the following equation :

R1+ R2 = RT

RT is the equivalent resistance. We have the value of both resistances, so we apply the ecuation:

R1 = 110Ω, and R2 = 560Ω

110Ω+ 560Ω = 670 Ω

When resistors are in parallel, resistors obey the following equation:

1/R1 + 1/R2= 1/RT

so, in our case:

1/ 110Ω +1/560Ω = 1/rt

0.01087Ω = 1/RT

RT= 1/0.01087 Ω= 91.94 Ω

answer: y=0 if that is what u r looking for

the first one is x^2+2x+2

the second one is x^2+4

the last one is x^2-4x+8