Mathematics, 13.09.2019 21:30, shemarmcdonald4662
Let a be the matrix: [130 024 154 11-4] find a basis for the nullspace of a.
Answers: 3
![{\left[\begin{array}{c}-1&-1&1&0\end{array}\right],\left[\begin{array}{c}-1&1&0&1\end{array}\right]}](/tpl/images/0230/3004/483e1.png)
![\left[\begin{array}{cccc}1&0&1&1\\3&2&5&1\\0&4&4&-4\end{array}\right]](/tpl/images/0230/3004/16869.png)
![\left[\begin{array}{cccc}1&0&1&1\\0&2&2&-2\\0&4&4&-4\end{array}\right]](/tpl/images/0230/3004/6cb5a.png)
![\left[\begin{array}{cccc}1&0&1&1\\0&2&2&-2\\0&0&0&0\end{array}\right]](/tpl/images/0230/3004/3b80c.png)
![\left[\begin{array}{cccc}1&0&1&1\\0&1&1&-1\\0&0&0&0\end{array}\right]](/tpl/images/0230/3004/33258.png)
![\left[\begin{array}{cccc}1&0&1&1\\0&1&1&-1\\0&0&0&0\end{array}\right] \left[\begin{array}{c}x_{1} &x_{2} &x_{3}&x_{4} \end{array}\right]=\left[\begin{array}{c}0&0&0\end{array}\right]](/tpl/images/0230/3004/abd4f.png)
then 
![\boldsymbol{x}=\left[\begin{array}{c}-s-t&s-t&t&s\end{array}\right]=\left[\begin{array}{c}-1&-1&1&0\end{array}\right]t+\left[\begin{array}{c}-1&1&0&1\end{array}\right]s\\\boldsymbol{x}=\left[\begin{array}{c}-1&-1&1&0\end{array}\right]x_{3} +\left[\begin{array}{c}-1&1&0&1\end{array}\right]x_{4}](/tpl/images/0230/3004/833bd.png)
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Let a be the matrix: [130 024 154 11-4] find a basis for the nullspace of a....
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