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which equation can be used to find y, the year in which
both bodies of water have the same amount of mercury?
the levels of mercury in two different bodies of water are
rising. in one body of water the initial measure of mercury
is 0.05 parts per billion (ppb) and is rising at a rate of 0.1
ppb each year. in the second body of water the initial
measure is 0.12 ppb and the rate of increase is 0.06 ppb
each year.
o 0.05 -0.1y = 0.12 - 0.06y
o 0.05y + 0.1 = 0.12y + 0.06
o 0.05 + 0.1y = 0.12 +0,06y
o 0.05y-0.1 = 0.12y - 0.06
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