Aprojectile is fired from a cliff 220 ft above water at an inclination of 45 degrees to the horizontal, with a muzzle velocity of 65 ft per secound. the height ,h, of the projectile abore water is given, h(x)=(-32x^2)/ ((65)^2 ) +x+220. x is the horizontal distance of the projectile from the face of the cliff. what is the maximum value of x?

248.79 ft

Step-by-step explanation:

A projectile is fired from a cliff 220 ft above water at an inclination of 45 degrees to the horizontal, with a muzzle velocity of 65 ft per second.

For maximum value of x, h(x)≥0

Solve quadratic equation for x

Using quadratic formula,

where, a=32, b=-4225, c=-929500

Hence, The maximum value of x will be 248.79 ft

your question is incomplete, write all the numbers in the sequence that it tells you.  

step-by-step explanation:

answer: 16

step-by-step explanation: first you would add 6+6 which equals 12 then add 2+2 which equals 4. then add 12 + 4 which is 16.

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