An urn contains three red balls, five white balls, and two black balls. four balls are drawn from the urn at random without replacement. for each red ball drawn, you win $6, and for each black ball drawn, you lose $9. let x represent your net winnings compute e(x), your expected net winnings e(x)

0

Step-by-step explanation:

total number of balls = 3+5+2= 10

Probability of getting red P(R) = 3/10

Probability of getting white P(W) = 5/10

Probability of getting black P(B) = 2/10

for each red ball drawn you win $6 and for each black ball drawn you loose $9 dollars

E(X)= 6×3/10 +0×5/10 -9×2/10= 0

E(X)= 0

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation: