Maria has a bag with 6 red marbles, 6 blue marbles, and 4 green marbles. without looking, maria picks one marble. she does not replace it, and she picks up another one. on the first pick, maria gets a green marble. what is the probability that she gets a red marble on her second pick? a. 4/15
b. 3/8
c. 2/5
d. 5/8

Hello there!

initially Maria has 6 red marbles, 6 blue marbles, and 4 green marbles.

You know that in the first pick, Maria gets a green marble ( this means that now there are 3 green marbles left)

Now we want to know the probability that she gets a red marble on the second pick.

Now there are 6 + 6 + 3 = 15 marbles in the bag, and 6 of them are red ones. Then the probability of getting one red is the number of red ones divided by the total amount ( which is the ratio of red marbles to total marbles)

this is 6/15.

now you can see that there is no 6/15 in the options, so we need to see which one is equivalent.

if we took the option C, 2/5, and multiply both denominator and numerator by 3, we get (3*2)/(3*5) = 6/15, then 2/5 and 6/15 are equivalents.

Then the correct answer is C.

okay wait before i answer, is this for your points on a graph?

you can not solvr this without numbers