Oco serves a tennis ball at vs = 50 m/s and charges the net at vc = 10 m/s. the opponent, x = 25 m away on the other side of the court, returns the ball with a speed half that of the serve. how close does coco get to the net (x/2 away) before she meets the return?

3.055 m

Step-by-step explanation:

In this solution we will use next notation:

=  time elapsed since oco serves the ball until it reaches its opponent.

=  time elapsed since the opponent returns the ball until it reaches oco.

d= Total distance traveled by Oco since serving the ball until  meeting the return.

We know that oco serves at vs = 50 m/s and her opponent is x=25 m away. Then, t_1 is given by

To compute t_2 observe that the return speed is 12.5 m/s and the distance that the ball will travel is . Then,

.

Therefore,

Finally, as Oco started 12.5m away from the net, when she meets the return she will be

away from the net.

12*c

step-by-step explanation:

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option