What is the cube of the difference of 40 and a number

(40-y)^3

Step-by-step explanation:

Make the unknown y

(40-y)^3

The difference can be expressed as

y=x³+120x²-4800x+64000

Or

y=(40-x)³

Step-by-step explanation:

Step one

To solve the problem problem let us first initialize the number to be x

By breaking the statement into component parts and implementing

Step two

1. The difference between 40 and the number

=(40-x)

2. The cube of the difference

= (40-x)³

Let us equate the expression to y

y=(40-x)³

Step three

Expanding the expression we have

y= (40-x)(40-x)(40-x)

Opening bracket we have

y=(1600-40x-40x+x²)(40-x)

y=64000-1600x-

1600x+40x²-1600x+40x²+40x²-x³

y=x³+120x²-4800x+64000

correct answer is infinitely many solutions

step-by-step explanation:

2(2x + 3) = -4 + 2(2x + 5)

solving the above equation:

4x + 6 = -4 +4x +10

combining like terms

4x -4x = -4+10-6

0=0

since both sides are 0=0, we end up into true statement it means it has infinite many solutions.

so correct answer is infinitely many solutions