In 2003, the population of zimbabwe
was about 12.6 million, which was
1 million more than 4 times the
population in 1950. write and solve an
equation to find the population p of
zimbabwe in 1950.

Step-by-step explanation:

12,600,000=1,000,000+4p where p is the population in 1950

12,600,000-1,000,000=4p

11,600,000=4p

11,600,000/4=p

p=2,900,000 is the population in 1950

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb