When the moving sidewalk at the airport is broken, as it often seems to be, it takes you 54s to walk from your gate to the baggage claim. when it is working and you stand on the moving sidewalk the entire way, without walking, it takes 83s to travel the same distance. how long will it take you to travel from the gate to baggage claim if you walk while riding of the moving sidewalk?

Your travel time will be 32.71 secs.

Step-by-step explanation:

Let the total distance be x feet.

Speed while walking = feet per second

Speed on the sidewalk = feet per second

Therefore, total speed while walking on moving sidewalk =

=

=

=

Hence, your travel time will be 32.71 secs.

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

5 + 8 +7 + 4 + 0 +1 = 25

step-by-step explanation: