You are on an alien planet where the names for substances and the units of measures are very unfamiliar. nonetheless, you obtain 84 quibs of a substance called skvarnick. you can trade this skvarnick for gold coins, but the vendors all measure skvarnick in units of sleps; not quibs. 11 quibs is equal to 13 sleps. if you have 84 quibs of skvarnick, how many sleps do you have?
round your answer to the nearest tenth (one decimal place.) type only the number; not the number and unit.

Evaluate 8x2 + 9x − 1 2x3 + 3x2 − 2x dx. solution since the degree of the numerator is less than the degree of the denominator, we don't need to divide. we factor the denominator as 2x3 + 3x2 − 2x = x(2x2 + 3x − 2) = x(2x − 1)(x + 2). since the denominator has three distinct linear factors, the partial fraction decomposition of the integrand has the form† 8x2 + 9x − 1 x(2x − 1)(x + 2) = correct: your answer is correct. to determine the values of a, b, and c, we multiply both sides of this equation by the product of the denominators, x(2x − 1)(x + 2), obtaining 8x2 + 9x − 1 = a correct: your answer is correct. (x + 2) + bx(x + 2) + cx(2x − 1).