Two boats leave port at the same time. one goes west and the other south. the speed of the southbound boat is 5 mph more than the westbound boat. after 3 hours the boats are 27 miles apart. find the speed of the southbound boat. round to the nearest tenth of a mile per hour.

Westbound boats speed = X

Southbound boats speed = X + 5

In 3 hours they are 27 miles apart:

3X + 3(x+5) = 27

Simplify:

3x + 3x +15 = 27

Combine like terms:

6x + 15 = 27

Subtract 15 from both sides:

6x = 12

Divide both sides by 6:

x = 12/6

x = 2

Westbound was 2 miles per hour

Southbound was 2 +5 = 7 miles per hour

Check:

2 miles per hour x 3 hours = 6 miles

7 miles per hour x 3 hours = 21 miles

21 + 6 = 27 miles

3 is greater then both of those numbers