A12-cm-long thin rod has the nonuniform charge density λ(x)=(2.0 nc/cm)e−|x|/(6.0 cm), where x is measured from the center of the rod. what is the total charge on the rod? hint: this exercise requires an integration. think about how to handle the absolute value sign

the total charge is

Step-by-step explanation:

Since x is measured from the center, that means that x=0 is the center so the edges of the rod correspond to x=-6 and x=6. that meas that the total charge can be calculated as

separating the integral from -6 to 0 and from 0 to 6, taking into account that |x|=-x for x<0 and |x|=x for x >=0, we get

using the substitution x=-u in the first integral we get

which is the same as the first integral. Thus, the total charge is given by

integrating we get

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1

i need a diagram

step-by-step explanation:

no