The length of a rectangle is 3 less than the width. determine how the area will change if the length of the rectangle is increased by 5 and the width is decreased by two. show your work.

At the beggining, if we called "b" to the length and "h" to the width, then the Area(A) = (h - 3) x (h) = h² - 3h.

In the final situation A = h² - 4

Step-by-step explanation:

Given A= b x h. At the beggining we have b = h -3 and h.                        So, A = (h - 3) x h ⇒ A = h² - 3h

In the second situation, b = (h - 3) + 5 and h= h - 2.

Then A= ((h - 3) + 5) x (h - 2) = (h - 3 + 5) x (h - 2) = (h + 2) x (h - 2)

⇒ A= h² - 2h + 2h - 4 ⇒ A= h² - 4.

step-by-step explanation:

∆abc has the points a(1, 7), b(-2, 2), and c(4, 2) as its vertices. formed with the point d(1, 2) as its third vertex, then ∆abd is triangle.

step-by-step explanation:

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