Mathematics

Mathematics, 11.09.2019 02:20, maevemboucher78

Write ach rational number in the form a/b where the integers 5 1/6

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Mathematics, 30.06.2019 18:30, someone2301

Why is the sum of two rational numbers always rational? select from the options to correctly complete the proof. \ let / and / represent two rational numbers. this means a, b, c, and d are (integers, natural numbers, imaginary numbers), and b is not (zero, rational, negative) and d is not (zero, rational, negative). the product of the numbers is / where bd is not 0. because integers are closed under (addition, subtraction, multiplication, division), / is the ratio of two integers making it a rational number.

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Mathematics, 13.07.2019 03:30, Weser17

Fill in the blanks of the following proof by contradicition that 7 + 4√2 is an irrational number. (you may use the fact that √2 is irrational.) proof: suppose not. that is suppose that 7 + 4√2 is (i) by definition of rational, 7 + 4√2 = a/b, where (ii) multiplying both sides by b gives 7b + 4b√2 = a so if we subtract 7b from both sides we have 4b√2 = (iii) dividing both sides by 4b gives √2 = (iv) but then √2 would be rational number because (v) this contradicts our knowlegde that √2 is irrational. hence the supposition is false and the given statement is true. a. (i). rational (ii). a and b are integers and b cannot equal 0 (iii). a+7b (iv). (a+7b)/4b (v). both a-7b and 4b are integers (since products and differences of interger are integers) and so √2 would be a rational number. b. (i). irrational (ii). a and b are integers and b cannot equal 0 (iii). a-7b (iv). (a-7b)/4b (v). both a-7b and 4b are integers (since products and differences of interger are integers) and so √2 would be a irrational number. c. (i). irrational (ii). a and b are integers and b cannot equal 0 (iii). a-7b ( a-7b)/4b (v). both a-7b and 4b are integers (since products and differences of interger are integers) and so √2 would be a rational number. d. b. (i). rational (ii). a and b are integers and b cannot equal 0 (iii). a-7b ( a-7b)/4b (v). both a-7b and 4b are integers (since products and differences of interger are integers) and so √2 would be a rational number.

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Mathematics, 26.07.2019 02:30, soystersoce

Which statement about rational numbers is not correct? a. all rational numbers are also integers. b. zero is a rational number. c. all integers are also rational numbers. d. all rational numbers can be written in the form a/b. i have seen this question asked several times but the answers are all over the place.

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Mathematics, 26.09.2019 01:00, khaylaperry

Write each rational number in the form, where a and b are integers.1.0.32.273. -54. 168. 0.116.7.34.5place each number in the correct place on the venn diagram.then list all the sets of numbers to which each number belongs.rational numbersintegerswhole numbers9. -1310.16 -11.012. 0.9913. -6.714. 34.15. -14

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