If f(x) = 2x + 6 and g(x) = x, what is (gºf)(0)?

(gºf)(0) is 6

Step-by-step explanation:

It is a composition of functions problem, where

(gºf) = g(f(x)) is the composition of the functions g(x) and f(x). (gºf)(0) is the composition of the functions at the point x = 0. First, we find that function that is the g composite of x, then we replace x by 0.

g(4), for example, is g when x = 4, right? So g(4) = 4.

So,

g(f(x)) is going to represent g when x = f(x). x = f(x) when x = 2x + 6, so:

g(f(x)) = g(2x+6) = 2x + 6

We have that

g(f(x)) = gºf(x) = 2x + 6

Now, we just have to find the value of the function at x = 0. So

gºf(0) = 2(0) + 6 = 0 + 6 = 6.

(gºf)(0) is 6

75

step-by-step explanation:

you do x-29=46 (the number of cantaloupes sold)

in order to find x, you have to find what minus 29 equals 46, meaning you'd have to add 29 to 46.

29+46=75

if you replace x with 75, the equation looks like:

75-29=46

x=75

yes   because as the functions are graphed they eventually will intersect unless otherwise

step-by-step explanation: