Arocket is divided into three sections: the payload and navigation section in the top, the fuel section in the middle, and the rocket engine section in the bottom. the top section is one-sixth the length of the bottom section. the middle section is one-half the length of the bottom section. the total length is 240 ft. find the length of each section?

Top part lenght= 24 ft.

Middle part= 72 ft.

Bottom part = 144 ft.

Step-by-step explanation:

First we assign varibales to each rocket part

top part length= x;

middle part length= y;

bottom part length= z;

Then from the reading we can write the next equations:

X=1/6 Z; (1)

Y=1/2 Z; (2)

X + Y +Z = 240 (3)

Then solving, we replace x and y, in the equation (3)

1/6 z + 1/2 z + z = 240

Multiply by 6 both sides:

6/6 z + 6/2 z + 6 z = 1440

z + 3 z + 6 z = 1440

Then grouping similar terms

10 z = 1440

z= 144

Then replacing in (1) and (2)

Y=1/2 *144=72

X=1/6*144= 24

answer: my brother can figure it out, imma go get him so i can answer : ) edit: my brother is sleeping, sorry man

step-by-step explanation:

simplifying

5(x + -6) = 2(x + 3)

reorder the terms:

5(-6 + x) = 2(x + 3)

(-6 * 5 + x * 5) = 2(x + 3)

(-30 + 5x) = 2(x + 3)

reorder the terms:

-30 + 5x = 2(3 + x)

-30 + 5x = (3 * 2 + x * 2)

-30 + 5x = (6 + 2x)

solving

-30 + 5x = 6 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-30 + 5x + -2x = 6 + 2x + -2x

combine like terms: 5x + -2x = 3x

-30 + 3x = 6 + 2x + -2x

combine like terms: 2x + -2x = 0

-30 + 3x = 6 + 0

-30 + 3x = 6

add '30' to each side of the equation.

-30 + 30 + 3x = 6 + 30

combine like terms: -30 + 30 = 0

0 + 3x = 6 + 30

3x = 6 + 30

combine like terms: 6 + 30 = 36

3x = 36

divide each side by '3'.

x = 12

simplifying

x = 12

this should .