The diameter of a biscuit is approximately 51 millimeters (mm). an atom of bismuth (bi) is approximately 320. picometers (pm) in diameter. calculate the number of bismuth atoms needed to span the diameter of a biscuit in a line. express your answer in scientific notation, showing the correct number of significant figures. (enter your answer using one of the following formats: 1.2e-3 for 0.0012 and 1.20e+2 for 120.

Bismuth atoms = 1,59375e+8

Step-by-step explanation:

Data: Biscuit diameter = 51 mm

         Bismuth (Bi) atom diameter = 320 pm

We need to calculate the number of bismuth atoms needed to span the diameter of a biscuit in a line. First we need to choose a unit to work with. In this case i'm going to use picometers.

We transform the biscuit diameter to picometer by using a rule of three:

1 mm = 1e+9 pm ⇒ 51 mm = 5,1e+10 pm

x = 5,1e+10 pm

Remember that:

1 m = 1e+12 pm

1 cm = 1e+10 pm

1 mm = 1e+9 pm

Now we calculate how many Bismuth atoms we need to span the diameter of a biscuit in a line:

00

step-by-step explanation: