Consider a job of 715 bytes that arrives for processing using a page size of 126 bytes, how many bytes would be loaded onto the last page of this job, and what would the number of that page be?

Total 6 pages will be consumed and 85 bytes will be on the 6th page.

Step-by-step explanation:

Let the number of pages used for the job = x

If the page size is 126 bytes.

Then total number of bytes used for the job = 126x

If these bytes are equal to 715 bytes then the equation will be

126x = 715

x =

  = 5.674 pages

That means 6 pages will be consumed.

and consumed bytes in 5 pages will be = 5×126 = 630 bytes

So remaining bytes will be on sixth page and the number will be = 715 - 630 = 85 bytes.

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb