Valeria is ordering medals for her school's track meet. company a charges $4.50 for each medal and a one-time engraving fee of $40. company b charges $6.50 for each medal and a one-time engraving fee of $20. which inequality can be used to find x, the least number of medals that can be ordered so that the total charge for company a is less than the total charge for company b? a) 4.5 + 40x < 6.5 + 20x b) 4.5 + 40x > 6.5 + 20x c) 4.5x + 40 < 6.5x + 20 d) 4.5x + 40 > 6.5x + 20

4.5x + 40 < 6.5x + 20

C is correct

Step-by-step explanation:

Valeria is ordering medals for her school's track meet.

Let total charge be $y and number of medals be x

#Company A charges $4.50 for each medal and a one-time engraving fee of $40.

 y = 4.5x + 40

#Company B charges $6.50 for each medal and a one-time engraving fee of $20.

 y = 6.5x + 20

The least number of medals that can be ordered so that the total charge for Company A is less than the total charge for Company B

Company A < Company B

   4.5x + 40 < 6.5x + 20

              2x > 20

                x > 10

Hence, The least value of x is 10 and inequality "  4.5x + 40 < 6.5x + 20 "

d) 30 units^2

area of rectangle = l × b

we know,

length = 10 unit

breadth = 3 unit

applying the formula,

= l × b

= 10 × 3

= 30 unit^2

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