Aschool gym is divided for a fair by bisecting its width and its length. each half of the length is then bisected, forming 8 sections in all. what are the dimensions and area of each section?

Dimensions will be

New Length= x/16 units

New width = y/2 units

Area=xy/32 square units

Step-by-step explanation:

Lets assume the dimensions of the school gym to be ;

Length= x

width= y

Length and width are first bisected for a fair.This means by a half

Length will be =x/2

Width will be =y/2

Then the length is divided to form 8 sections that are equal, which will ;

(x/2)÷8

x/2 * 1/8 = x/16 units

New length = x/16 units in dimension

New width will be y/2 units in dimension

Area of each section will be;

length by width

(x/16 )*(y/2)

=xy/32 square units

answer:

it is general formula that is used to write value to its excet position

a11 a12 a13

a21 a22 a23

it is the example of order 2 by 3 matrix in this

a11 means value occur in 1 st row 1st column

a12 means value occurs in 1st row 2nd column

a13 means value occur in 1st row and 3rd column

a21 means value occurs in 2nd row and 1st column

a22 means value occurs in 2nd row and in 2nd column

a23 means value occurs in 2nd row and in 3rd column

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,