22. francisco is three years more than twice jenna's age. harrison is two years less than three times jenna's age.
if jenna's age is given by a, then write an expression for francisco's age, harrison's age, and the sum of all
three ages, in terms of a.

An expression for Francisco's age in terms of a is (2a+3)

An expression for Harrison's age in terms of a is (3a-2)

An expression for the sum of all  three ages, in terms of a is (6a+1)

Step-by-step explanation:

Let

a > Jenna's age

b > Francisco's age

c > Harrison's age

we know that

Francisco's age is two times Jenna's age plus three years

b=2a+3 > equation A

Harrison's age is three times Jenna's age minus two years

c=3a-2 > equation B

The sum of all  three ages, in terms of a is

(a+b+c) > equation C

substitute equation A and equation B in equation C

a+(2a+3)+(3a-2)

Combine like terms

(a+2a+3a)+(3-2)

6a+1

therefore

An expression for Francisco's age in terms of a is (2a+3)

An expression for Harrison's age in terms of a is (3a-2)

An expression for the sum of all  three ages, in terms of a is (6a+1)

r and t.

both are 64 degrees.