Suppose that a rancher has '1 000 feet of fencing available to make a rectangular corral. a barn will form one side of the corral so no fencing will be needed there. what dimensions will give the maximum area?

x=250 ft    y= 500ft

Step-by-step explanation:

Peremiter of the rectangle= 2x+2y

Perimeter= 2x+y=1000   (equation 1)

Remember that the perimterer of  any polygon is the sum of its lenghts of all sides So 1000 ft of fencing available  has to be the the sum of the lengths of the rectangular corral.

     3. There are two unknown variables in the equation 1.  Any of them can be solved  . In this case we will choose y

y=1000  - 2x   (equation 2)

Now In order to get  the maximum area of the corral,  we are going to define   Area.

A(x,y)=x*y  

    4. Substitute y in the area equation.

A(x)=x*(1000-2x)

Then apply distributive property, therefore:

4.  A=1000x-2x² (equation 3)

Since we want to get the maximum area, the next step is to  find a local maximum of the function. This is possible through the  first derivative =0 (first derivative test)

5.  A'(x)=1000-4x=0

Then , solve for x

4x=1000

x=1000/4

x=250

6.  Replace value of x in equation 2.

y=1000- 2(250)

y=500

In conclusion, the dimensions that will give the maximum area of the corral are: 250 ft and 500 ft

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

a

step-by-step explanation: