If ( look at the picture ) and d(x) = x + 3, what is the domain of (cd)(x)?
-all real values of x
-all real values of x except x = 2
-all real values of x except x = –3
-all real values of x except x = 2 and x = –3

Hi!

so you have and

The first thing you can notice is that the domain of c is all reals minus the number 2 (because the denominator is 0), and the domain of d is al the reals.

then

Again the only problem here is when x = 2, because the denominator is zero in that case, then the domain of (cd)(x) is al real values except x = 2, which is the second option

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3