10. one circle has an equation of (x + 5)+ (y-2)2 = 81. a second circle has center at
(8,4) with a radius of 1. what is the midpoint of the line segment that connects the
two centers?

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

i think 5 miles per hour

step-by-step explanation:

40 i don’t know lololol