If (m, 1) is on a circle with center (8, 1) and radius 7, what is a value of m?

a)m=1
b)m=-1
c)m=14
d)m=-8=-+sqrt33

The equation for the circle is:

(x-8)^2 + (y-1)^2 = 49

If we take 'y' as 1, then

(x-8)^2 + 0 = 49

x-8 = √49

x = ±7 + 8

x = 15 or x = 1

b

step-by-step explanation:

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752