Abee flies at 10 feet per second directly to a flowerbed from its hive. the bee stays at the flowerbed for 11 minutes, and then flies directly back to the hive at 6 feet per second. it is away from the hive for a total of 15 minutes. a. what equation can you use to find the distance of the flowerbed from the hive? b. how far is the flowerbed from the hive? a. write the equation. let d be the distance of the flowerbed from the hive.

(a)

Equation is

(b)900ft

Step-by-step explanation:

Let the distance of flower bed from hive to be d

Time the bee stays at the flower bed=11

Time the bee is away from the hive=15

Time the bed was flying to the flower bed and back to the hive will be;

15 -11=4 minutes--------------changes to seconds by multiplying by 60

=4*60=240 seconds

Formular for time is Distance/speed

Time of fright=240 seconds

Form expression for time of flying;

Time for flying from hive to flowerbed= d/10ft/s

Time for flying from flower bed to Hive= d/6ft/s

=This means

(a) Equation is

(b) The flower bed is 900ft away from the hive

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.