The international business club starts the school year with $250.50 in their account. they spend $35 each month on activities. the future agricultural leaders club starts with $300 and spends $45.25 each month. which equation can be used to find m, the number of months it will take for both accounts to have the same amount of money?

m= 4.8 months

Step-by-step explanation:

by taking  x as the money the International Business Club has at any time of the year,250.5 for their initial money, 35 as the money they spend every month and m being the month that have passed since the beginning of the school year; it all can be related to the following equation:  

x= 250.5 - (35*m)

And doing the same thing with the money from the Future Agricultural Leaders Club, associating their money to the variable y, the equation would be:

y=300 - (45.25*m)

as it is wanted to know at what month does both clubs have the same amount of money, x and y, must be the same, so:

250.5 - (35*m)  =300  - (45.25*m)

this equation can be solved by putting both terms that are related to m on the same side of the equality, and those who aren’t related on the other side:

(45.25*m)  - (35*m)= 300  -250.5

then, on the first side of the equation, m  can be taken out as common factor:

(45.35-35)*m=49,5

and solving for m:

m=

m=4.8  

250.5 – 35m = 300 – 45.25m

Step-by-step explanation: passed the test on edg;)

when studying polynomials, you often hear the terms zeros, roots, factors and x x the multiplicity of a zero is important because it tells us how the graph of the let's look at the graph of a function that has the same zeros

step-by-step explanation: