Is it ever possible that sin (a+b)= sin⁡ a+sin⁡ b? if so, explain how. if not, explain why not.
i really don't understand the sum identity for sine. it's frustrating me to the core. somebody .

 yes, when A & B are on the quadrantals (0°, 90°, 180°, 270°)          which results in a sum of 0

Step-by-step explanation:

sin (A + B) = cos A · sin B  +  cos B · sin A

If cos A = 1 and cos B = 1, then you will end up with sin A + sin B.

The only angle where cos is equal to 1 is at 0°. Notice that sin is equal to 0.

It follows that when cos is equal to -1, sin is also 0. This occurs at 180°

The other option is when cos is equal to 0. This occurs at 90° and 270°.

All of these options result in sin A + sin B = 0

So, the only possibility when sin (A + B) = sin A + sin B is when it equals zero.

t = 3

step-by-step explanation:

put t = 3 in this expression :

(3²-1)(3²-2)(3² - 3)(3² - 4) = 8×7×6×5 = 56×30 = 1680

step-by-step explanation:

i believe its "c" because all of the other options include a but it could be d because there is a way of financing with cash at certain places but its uncommon.