Acube is located such that its bottom four corners have the coordinates (−1,−3,−2), (−1,4,−2), (6,−3,−2) and (6,4,−2). give the coordinates of the center of the cube.

The co-ordinates of the center of the cube are (-2.5,0.5,1.5)

Step-by-step explanation:

Since the 'z' co-ordinate of all the points is same hence we can conclude that all the given 4 points are planar.

Thus the problem reduces a planar problem with need to find the center of the square with vertices (-1,-3), (-1,4), (6,-3), (6,4)

Thus the length of the side of the square is

The center of the square is given by taking (-1,-3) as reference co-ordinate

(-1+7/2,-3+7/2) = (-2.5,0.5)

Now since center lies above this center of base

Thus the coordinates of the center of the cube are given by (-2.5,0.5,-2+3.5)=(-2.5,0.5,1.5)

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step-by-step explanation: