Let n be a positive integer and define [n] to be the set of the first n positive integers. that is, [n] = {1, 2, 3, . . , n}. we want to select two disjoint, possibly empty subsets a, b of [n]. in how many ways can we do this?

There are ways of doing this

Hi!

To solve this problem we can think in term of binary numbers. Let's start with an example:

n=5,  A = {1, 2 ,3},  B = {4,5}

We can think of A as 11100, number 1 meaning "this element is in A" and number 0 meaning "this element is not in A"

And we can think of B as 00011.

Thinking like this, the empty set is 00000, and [n] =11111 (this is the case A=empty set, B=[n])

This representation is a 5 digit binary number. There are of these numbers. Each one of this is a possible selection of A and B. But there are repetitions: 11100 is the same selection as 00011. So we have to divide by two. The total number of ways of selecting A and B is the .

This can be easily generalized to n bits.

1/3

step-by-step explanation:

to find this, you can divide 12 by 4 which is 3 or you can multiply 4 until you reach 12 (4x3=12). both should give you 3, meaning theres three times less bananas than there are oranges.

they can both be solutions depends on the equation

step-by-step explanation:

what is the equation? ?