Abus lets off a quarter of its passengers and take up 7 more passengers for every stop. if the bus went through 3 stops, what is the smallest possible number of initial passengers?

28

Step-by-step explanation:

The initial number n must be a multiple of 4 (otherwise n/4 will not be an integer) and must be bigger than 0. Therefore if the initial number is less than 28 then it should be a number in the next list: 4, 8, 12, 16, 20 and 24, but from those options just 12 could give a second stop but not a third stop.

so the smallest number that allow three stops is 28 since:

Therefore 28 could not only stop three times but infinite times.

answer: i don't understand. what are the options

step-by-step explanation:

24

step-by-step explanation:

if it takes 8 pounds to make 12 divide 12 by 8 and you get 1.5, 1.5 x 16 = 24