The last digit of the heights of 40 statistics students were obtained as part of an experiment conducted for a class. use the frequency distribution to the right to construct a histogram. what can be conducted from the distribution of the digits? specifically, do the heights appear to be reported or actually measured? choose the correct histogram below. are the data reported or measured?
a. the data appears to be measured. certain heights occur a disproportional number of times.
b. the data appears to be reported. the heights occur with roughly the same frequency.
c. the data appears to be measured. the heights occur with roughly the same frequency.
d. the data appears to be reported. certain heights occur a disproportional number of times.

D. The data appears to be reported. Certain heights occur a disproportional number of times.

Step-by-step explanation:

Given the tables as show below;

Digit                                                    Frequency

0                                                              14

1                                                                3

2                                                                3

3                                                                3

4                                                                4

5                                                                13

6                                                                 3

7                                                                 5

8                                                                 3

9                                                                 5

You can construct the histogram as shown in the attached file and interpret it.

You notice that certain heights occur a disproportionate number of times. For example, at a frequency of 3, you have heights 2, 3,6 and 8, where as at a frequency of 5 , you have height 7 and 9.

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

a

step-by-step explanation: