Apizza restaurant sold 24 cheese pizzas and 16 pizzas with one or more toppings. twelve of the cheese pizzas were eaten, and 10 of the pizzas with one or more toppings were eaten at work. if a pizza was selected at random, find the probability of each: a. it was a cheese pizza eaten at work. b. it was a pizza with either one or more toppings, and it was not eaten at work. c. it was a cheese pizza, or it was a pizza eaten at work.

Step-by-step explanation:

                                cheese  With toppings    Total

No of pizzas sold    24                     16                40

Eaten at work           12                     10                22

Not eaten at work     12                      6                18

a) Prob for a cheese pizza eaten at work=

b) Prob a pizza with either one or more toppings, and it was not eaten at work.=

c) Prob for a cheese pizza, or it was a pizza eaten at work.=P(cheese)+P(pizza eaten at work)-P(both)

=

the number of the people going.

step-by-step explanation:

the cost to buy one movie ticket is $7. if the total cost for the movie is a function of how many people go, then the input is : the number of the people going.

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v