Atypical person has an average heart rate of 70.0 beats/min. calculate the given questions. how many beats does she have in 4.0 years? how many beats in 4.00 years? and finally, how many beats in 4.000 years? pay close attention to significant figures in this question.

147168000 beats

Step-by-step explanation:

Given,

The average heart rate is 70.0 beats/min.

That is, the number of heart beat in one minute = 70,

∵ 1 year = 365 days, 1 day = 24 hours, 1 hour = 60 minutes,

So, the number of minutes in 1 years = 365 × 60 × 24 × 1 = 525600

Thus, the number of minutes in 4 years = 4 × 525600 = 2102400,

So, the number of heart beats in 2102400 minutes = 70 × 2102400 = 147168000

Hence, the number of heart beats in 4 years is 14716800,

Now, 4 can be written as 4.0, 4.00 or 4.000,

That is, if we add zeros after decimal the number does not change.

Therefore, the number of heart beats in 4, 4.0, 4.00 and 4.00 would be same.

add 5 subtract 1

step-by-step explanation:

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3