You have just used the network planning model and found the critical path length is 30 days and the variance of the critical path is 25 days. the probability that the project will be completed in 33 days or less is equal to (2 decimal accuracy)

The probability that the project will be completed in 33 days or less is equal to 0.73 .

Step-by-step explanation:

We assume that this is a normally distribution.

Given : The critical path length is 30 days .

i.e. Population mean =

Variance :

Then, standard deviation :

Z-score :  

The value of z corresponding to 33 =

Now, the p-value =

Hence, the probability that the project will be completed in 33 days or less is equal to 0.73.

.25

step-by-step explanation:

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